…you know the term “thin-slicing.” That describes an experienced consultant’s approach to the problem very well. The…you‘ve seen there really isn’t any such thing. Post your questions in the comments, and I’ll try to answer…
Post: How Percona strives to remain neutral and independent
…Peter‘s post on bias) based on our knowledge of the product, regardless of whether the…the product. The more we know, the more valuable we can be to you and to our clients who might purchase the…to speak. The answer is that vendors might not be ready with their product. We aren’t here to…
Post: Heikki Tuuri Innodb answers - Part I
…to guess where our search would end in the B-tree. To verify that we arrived at the right position, we need to know the…to whatever use in whatever segment. After that, a segment always reserves whole 64 page extents. Thus, the answer to the…
Post: Heikki Tuuri answers to Innodb questions, Part II
…answers to the second portions of the questions you asked Heikki. If you have not seen the…the web about flash memories, and noticed that random writes to them are actually slower than to a mechanical disk. I do not know how…
Post: How Percona diagnoses MySQL server stalls
…the conditions occur. Analyze the diagnostic data. The answer will usually be obvious. Step 1 is usually pretty simple, but it’s the most important to…
Post: Percona Server with XtraDB Case Study, Behind the Scenes
…the right data. Maybe you have too little, or too much, or you have the signal mixed in with the noise. Knowing when and how to…to do was wait until the problem happened, look at the diagnostics, and a couple minutes later I had my answer. What were the problems? The…
Comment: COUNT(*) vs COUNT(col)
…the performance of counting all the rows in a table. This discussion is a good example of Peter‘s other comments today … simple answers…to have a more complete understanding of the technology, so you can make the best decisions on how to apply it to…
Comment: MySQL Server Memory Usage
…to know is howto track down where the bottleneck is… I’ve read Peter Z two guides but cannot really convert the gained knowledge to…the answer to ‘b’ is 2mb then the total amount of memory would be something like 1800 + 2*600 = 3G right? To much to…

